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'AUSbord' rose Description
'Gertrude Jekyll ®' rose photo
Photo courtesy of Pascale Hiemann
Availability:
Commercially available
HMF Ratings:
177 favorite votes.  
Average rating: EXCELLENT-.  
ARS:
Medium pink Shrub.
Registration name: AUSbord
Origin:
Bred by David C. H. Austin (1926-2018) (United Kingdom, 1986).
Class:
Found Rose, Shrub.   (Series: English Rose Collection)  
Bloom:
Pink. [Pink, lighter edges, lighter reverse.]  Glandular pedicels. Prickly.  Strong, old rose fragrance.  Average diameter 4.25".  Large, very double, old-fashioned, quartered bloom form.  Blooms in flushes throughout the season.  
Habit:

Height: 4' to 10' (120 to 305cm).  Width: 4' to 6' (120 to 185cm).
Growing:
USDA zone 5b through 10b.  Spring Pruning: Remove old canes and dead or diseased wood and cut back canes that cross. In warmer climates, cut back the remaining canes by about one-third. In colder areas, you'll probably find you'll have to prune a little more than that.  
Patents:
Australia - Application No: 1991/021  on  22 Mar 1991   VIEW PBR PATENT
Synonym: Gertrude Jekyll. Applicant: David Austin Roses Ltd.
 
New Zealand - Patent No: 522  on  20 Aug 1990
Application  on  9 Mar 1989
The breeder's Reference for this rose is Ausbord. The New Zealand Trade Name is 'Gertrude Jekyll'. This PVR Grant expires August 20, 2013.
 
United States - Patent No: PP 7,220  on  17 Apr 1990   VIEW USPTO PATENT
The patent application reports the following parentage:
Female parent (seed parent): An unnamed seedling.
Male parent (pollen parent): Comte de Chambord.
Notes:
“Von Doussa Children” Found in the Adelaide Hills, South Australia. John Nieuwesteeg, has identified this rose as Gertrude Jekyll.