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Discussion id : 52-920
most recent 18 MAR 11 HIDE POSTS
 
Initial post 17 MAR 11 by Erichtonius
Unindentified centifolia rose (maybe "Gaspard Monge", centifolia, Robert, 1854)

I need some help to identify a wonderful, perfectly shaped and strongly fragrant rose I first discovered under an old yew in my garden in Normandy, about 17 years ago.
It has all the characteristics of a centifolia rose. It forms an open bush, up to 1,30 m, with long and flexible branches, quite thornless, with bright green foliage, of medium to large size, and numerous buds of globular form, which bloom one month long between may and june, in a very double cup form of deep pink, with silver shading on the outside and lilac inside, with a strong typical fragrance of Centifolia. It is very vigorous and has a great tendency to produce suckers. It may be subject to rust, and a part of its buds often rot before opening. It may be different in a Mediterranean climate, I don't know.
I compared it with most gallica, without finding a close one. I have finally found a centifolia which seems quite identical to mine : "Gaspard Monge", but without certainty.
If a botanist is interested, I have several specimens of it. Thank you in advance.
REPLY
Reply #1 of 4 posted 18 MAR 11 by Patricia Routley
The 'Charles Lawson' of commerce?
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Reply #2 of 4 posted 18 MAR 11 by Erichtonius
I don't think so ; "Charles Lawson" is a re-blooming Bourbon (mine is once-blooming), with larger blooms, and of a deeper shade of pink. But, actually, it's quite similar.
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Reply #3 of 4 posted 18 MAR 11 by Patricia Routley
Thanks for the heads-up on the re-blooming of 'Charles Lawson'.
Your description of your unidentified centifolia rose sounded very much like the description (in the Charles Lawson comments) of some Australian foundlings. However as the Australian foundlings are all once-blooming as well, I think it is time to move my photos into a file of their own. (One of the names I will use will be the "Brooks Rose") I initially placed my photos in the 'Charles Lawson' file because the Australian foundlings seem to be the same as Lee Sherman's and Jannorcal's 12th Avenue Smoothie photos.
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Reply #4 of 4 posted 18 MAR 11 by Erichtonius
Here is a picture of "Charles Lawson", grown by Roseraie Loubert in France : http://www.rosesloubert.com/collection%20loubert/2002/charles%20lawson.jpg. I don't grow it myself, but I know it forms a high shrub, like many Bourbons, up to 4 m.
But your "Brook's rose" seems very close to mine in your picture indeed, as "12th Avenue Smoothie". I will look for "Charles Lawson" in parisian rose gardens.
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